問題描述

我將創建一個由十六進制值組成的序列號

I will be creating a sequential Serial Number made from Hexadecimal values

使用這種格式:

XX-XX-XX-YYYY
Which XX-XX-XX is default value
And YYYY is the incrementing hexa decimal value

現在要根據十六進制值創建序列號，我需要將 6 添加到最后生成的十六進制值

Now to create the serial number based on hex value I need Add 6 to the last generated hex value

MIN: 2D41 + 6 = 2D47    
     2D47 + 6 ... and so on
MAX: 4100   generation of serial will stop when I meet the MAX value.

我已經在 c# 中創建了它，但我需要在 SQL 上進行

I already created it in c# but I need to do it on SQL

int num1 = int.Parse("2D41", NumberStyles.HexNumber); //Convert hex to int
int result = num1 + 6; //Add + 6 for increment
string myHex = result.ToString("X");  //Convert result to hex
MessageBox.Show(myHex);  // result 2D47

如何在 T-SQL 中做到這一點?

How can this be done in T-SQL?

推薦答案

希望對你有幫助

declare @seed varchar(max) = '2D41';
declare @limit varchar(max) = '4100';

select convert(int, convert(varbinary(max), '0x'+@seed,1)),
       convert(int, convert(varbinary(max), '0x'+@limit,1));

;with seedlimit(seed, limit) as (
    select convert(int, convert(varbinary(max), '0x'+@seed,1)),
           convert(int, convert(varbinary(max), '0x'+@limit,1))
)
select SerialNumber = 'XX-XX-XX-' + right(convert(varchar(10),cast(s.seed + 6 * v.number as varbinary(max)),1),4)
from seedlimit s
join master.dbo.spt_values v on type='p'
where s.seed + 6 * v.number <= s.limit;

您可以根據答案創建視圖/過程/函數的基本成分，

The basic ingredients are in there for you to create a view/procedure/function out of the answer,

輸出:

SerialNumber
-------------
XX-XX-XX-2D41
XX-XX-XX-2D47
...
XX-XX-XX-40F7
XX-XX-XX-40FD

這篇關于將十六進制轉換為 INT，反之亦然的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！