問題描述
我一直在讀這樣的句子
不要依賴 1 個字節的大小為 8 位
don't rely on 1 byte being 8 bit in size
使用 CHAR_BIT 而不是 8 作為常量在位和字節之間轉換
use CHAR_BIT instead of 8 as a constant to convert between bits and bytes
等等.今天有哪些現實生活系統，這適用于哪些地方?(我不確定 C 和 C++ 在這方面是否存在差異，或者它是否實際上與語言無關.如有必要，請重新標記.)
et cetera. What real life systems are there today, where this holds true? (I'm not sure if there are differences between C and C++ regarding this, or if it's actually language agnostic. Please retag if neccessary.)
推薦答案
在較舊的機器上，小于 8 位的代碼相當普遍，但其中大部分已經消失多年了.
On older machines, codes smaller than 8 bits were fairly common, but most of those have been dead and gone for years now.
C 和 C++ 已經規定 char 的最少為 8 位，至少可以追溯到 C89 標準..他們將char"和byte"視為本質上是同義詞
C and C++ have mandated a minimum of 8 bits for char, at least as far back as the C89 standard. . They treat "char" and "byte" as essentially synonymous
然而，當前的機器(主要是 DSP)的最小類型大于 8 位——至少 12、14 甚至 16 位是相當常見的.Windows CE 的做法大致相同:它的最小類型(至少對于 Microsoft 的編譯器)是 16 位.然而，他們不將 char 視為 16 位 - 相反，他們采用(不符合)的方法，簡單地不支持名為 char<的類型/code> .
There are, however, current machines (mostly DSPs) where the smallest type is larger than 8 bits -- a minimum of 12, 14, or even 16 bits is fairly common. Windows CE does roughly the same: its smallest type (at least with Microsoft's compiler) is 16 bits. They do not, however, treat a char as 16 bits -- instead they take the (non-conforming) approach of simply not supporting a type named char at all.
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