問題描述

我設置了一個QT菜單，它自動連接到動作函數on_actionOpen_triggered().后來我想將文件名字符串傳遞給這個函數，以便在特殊情況下手動調用這個函數.所以我將函數簽名更改為 on_actionOpen_triggered( const char *filename_in ).修改后程序運行良好，但終端報錯，

I set a QT menu, which is automatically connected with action function on_actionOpen_triggered(). Later I want to pass a filename string to this function in order to call this function manually in a special condition. So I changed the function signature to on_actionOpen_triggered( const char *filename_in ). After this change the program is running well, but there is a complain in terminal,

QMetaObject::connectSlotsByName: on_actionOpen_triggered(const char*) 沒有匹配的信號

QMetaObject::connectSlotsByName: No matching signal for on_actionOpen_triggered(const char*)

我想知道發生了什么，以及如何為此菜單操作功能添加參數.

I am wondering what happened, and how I can add arguments for this menu action functions.

謝謝.

推薦答案

我遇到了同樣的警告/錯誤 QMetaObject::connectSlotsByName: No matching signal for

并得到了簡單的解決方案.例如:

And got simple solution. For Example:

問題:
QMetaObject::connectSlotsByName: on_actionOpen_triggered(const char*) 沒有匹配的信號 警告您只需要更改 Slot

Problem :
QMetaObject::connectSlotsByName: No matching signal for on_actionOpen_triggered(const char*) Warning You just need to change the name of the Slot

解決方案
更改插槽名稱，如 on_actionOpenTriggered，此警告消失.

提示
Qt 嘗試理解其默認插槽，如 on__，因此如果您指定任何具有上述簽名的插槽，Qt 將拋出警告.

Hint
Qt try to understand its default slot like on_<name_of_object>_<action>, So if you specify any slot with above signature, Qt will throw warning.

希望對大家有所幫助.

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