問題描述

來自 boost 庫的 Circular_buffer 不是線程安全的.所以我將 boost::circular_buffer 對象包裝在一個類中，如下所示.線程之間的互斥是通過使用條件變量、互斥鎖和鎖獲取/釋放來實現的(我認為).這個實現線程安全嗎?

Circular_buffer from boost library is not thread-safe. So I wrapped boost::circular_buffer object in a class as shown below. Mutual exclusion between the threads is achieved (I think) by using conditional variables, a mutex and a lock acquisition/release. Is this implementation thread safe?

#include <boost/thread/condition.hpp>
#include <boost/thread/mutex.hpp>
#include <boost/thread/thread.hpp>
#include <boost/circular_buffer.hpp>

// Thread safe circular buffer 
template <typename T>
class circ_buffer : private boost::noncopyable
{
public:
    typedef boost::mutex::scoped_lock lock;
    circ_buffer() {}
    circ_buffer(int n) {cb.set_capacity(n);}
    void send (T imdata) {
        lock lk(monitor);
        cb.push_back(imdata);
        buffer_not_empty.notify_one();
    }
    T receive() {
        lock lk(monitor);
        while (cb.empty())
            buffer_not_empty.wait(lk);
        T imdata = cb.front();
        cb.pop_front();
        return imdata;
    }
    void clear() {
        lock lk(monitor);
        cb.clear();
    }
    int size() {
        lock lk(monitor);
        return cb.size();
    }
    void set_capacity(int capacity) {
        lock lk(monitor);
        cb.set_capacity(capacity);
    }
private:
    boost::condition buffer_not_empty;
    boost::mutex monitor;
    boost::circular_buffer<T> cb;
};

Edit 這現在是一個模板類，它接受任何類型的對象(不僅僅是 cv::Mat 對象).

Edit This is now a template class, which accepts an object of any type (not just cv::Mat object).

推薦答案

是.
如果您使用相同的鎖鎖定所有公共方法，它將是線程安全的.

Yes.
If you lock all the public methods with the same lock it will be threadsafe.

您可以考慮使用讀寫鎖，如果您使用它可能會有更好的性能有很多并發讀者.

You could consider using read-write locks, which may have better performance if you have a lot of concurrent readers.

如果你沒有很多讀者，它只會增加開銷，但可能值得檢查選項和測試.

If you don't have a lot of readers, it will just add overhead, but may be worth checking the option and testing.

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