本文介紹了如何計算轉彎方向的處理方法，對大家解決問題具有一定的參考價值，需要的朋友們下面隨著小編來一起學習吧！
問題描述
我有一個三個緯度坐標，它們組成兩條線段 A 到 B 到 C.我還發現了一個函數，可以以 -180 到 180 的方式返回線段 A-B 或 B-C 的北向.但是，我無法確定汽車何時從 A 到達 B，應該右轉還是左轉繼續前往 C.
I have a three lat-lon coordinates that make up two line segment A to B to C. I also found a function that can return north-bearing of a line segment A-B or B-C in -180 to 180 manner. However, I'm having trouble to determine when a car reaches from A to B, should it turn right or left to continue to C.
推薦答案
之前的答案是錯誤的.現在這是正確的
Previous answer was wrong. now this is the correct
public Direction GetDirection(Point a, Point b, Point c)
{
double theta1 = GetAngle(a, b);
double theta2 = GetAngle(b, c);
double delta = NormalizeAngle(theta2 - theta1);
if ( delta == 0 )
return Direction.Straight;
else if ( delta == Math.PI )
return Direction.Backwards;
else if ( delta < Math.PI )
return Direction.Left;
else return Direction.Right;
}
private Double GetAngle(Point p1, Point p2)
{
Double angleFromXAxis = Math.Atan ((p2.Y - p1.Y ) / (p2.X - p1.X ) ); // where y = m * x + K
return p2.X - p1.X < 0 ? m + Math.PI : m ); // The will go to the correct Quadrant
}
private Double NormalizeAngle(Double angle)
{
return angle < 0 ? angle + 2 * Math.PI : angle; //This will make sure angle is [0..2PI]
}
這篇關于如何計算轉彎方向的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！
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