問題描述

protected int parseExpire(CacheContext ctx) throws AttributeDefineException {
    Method targetMethod = ctx.getTargetMethod();
    CacheEnable cacheEnable = targetMethod.getAnnotation(CacheEnable.class);
    ExpireExpr cacheExpire = targetMethod.getAnnotation(ExpireExpr.class);
    // check for duplicate setting
    if (cacheEnable.expire() != CacheAttribute.DO_NOT_EXPIRE && cacheExpire != null) {
        throw new AttributeDefineException("expire are defined both in @CacheEnable and @ExpireExpr");
    }
    // expire time defined in @CacheEnable or @ExpireExpr
    return cacheEnable.expire() != CacheAttribute.DO_NOT_EXPIRE ? cacheEnable.expire() : parseExpireExpr(cacheExpire, ctx.getArgument());
}

這是測試的方法，

Method targetMethod = ctx.getTargetMethod();
CacheEnable cacheEnable = targetMethod.getAnnotation(CacheEnable.class);

我必須模擬三個 CacheContext、Method 和 CacheEnable.有什么想法可以讓測試用例變得更簡單嗎?

I have to mock three CacheContext,Method and CacheEnable. Is there any idea to make the test case much simpler?

推薦答案

Mockito 可以處理鏈式存根:

Foo mock = mock(Foo.class, RETURNS_DEEP_STUBS);

// note that we're stubbing a chain of methods here: getBar().getName()
when(mock.getBar().getName()).thenReturn("deep");

// note that we're chaining method calls: getBar().getName()
assertEquals("deep", mock.getBar().getName());

AFAIK，鏈中的第一個方法返回一個模擬，它被設置為在第二個鏈接方法調用時返回您的值.

AFAIK, the first method in the chain returns a mock, which is set up to return your value on the second chained method call.

Mockito 的作者指出，這應該僅用于遺留代碼.更好的做法是將行為推送到您的 CacheContext 中，并提供它自己完成工作所需的任何信息.您從 CacheContext 提取的信息量表明您的課程具有 功能嫉妒.

Mockito's authors note that this should only be used for legacy code. A better thing to do otherwise is to push the behavior into your CacheContext and provide any information it needs to do the job itself. The amount of information you're pulling from CacheContext suggests that your class has feature envy.

這篇關于鏈式調用的模擬或存根的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！