問題描述
我需要將一個(gè)非常大的二進(jìn)制值轉(zhuǎn)換為其十進(jìn)制等效值.因?yàn)樗且粋€(gè)大整數(shù)，所以我使用的是 BigInteger.那么如何將此二進(jìn)制數(shù)轉(zhuǎn)換為 BigInteger?
I needed to convert a very big binary value into its decimal equivalent. As it is a big integer I was using BigInteger. So how do I convert this binary number to a BigInteger?
推薦答案
如果你有二進(jìn)制數(shù)的 String 表示，將它提供給這個(gè)重載的 BigInteger 構(gòu)造函數(shù)以創(chuàng)建一個(gè)實(shí)例:
If you have the String representation of your binary number, provide it to this overloaded BigInteger constructor to create an instance:
BigInteger(String val, int radix);
在你的情況下，基數(shù)顯然是 2，即你可以使用這樣的東西:
In your case, radix is clearly 2, i.e. you can use something like this:
BigInteger yourNumber = new BigInteger("101000101110...1010", 2);
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