問題描述

正如標題所說，我該怎么做?它很容易從字符串 -> 字節 -> 字符串二進制轉換，但是我如何轉換回來?下面是一個例子.輸出是:'f' 到二進制:01100110294984

我在某處讀到可以使用 Integer.parseInt 但顯然不是這樣 :( 還是我做錯了什么?

謝謝，:)

公共類主{公共靜態無效主要(字符串[]參數){字符串 s = "f";字節[] 字節 = s.getBytes();StringBuilder 二進制 = new StringBuilder();對于(字節 b:字節){詮釋價值 = b;for (int i = 0; i <8; i++){binary.append((val & 128) == 0 ? 0 : 1);val <<= 1;}binary.append(' ');}System.out.println("'" + s + "' 轉二進制:" + binary);System.out.println(Integer.parseInt("01100110", 2));}}

你可以使用Byte.parseByte() 基數為 2:

byte b = Byte.parseByte(str, 2);

<小時>

使用您的示例:

System.out.println(Byte.parseByte("01100110", 2));

<上一頁>102

as the title says, how do I do it? Its easy to convert from string -> byte -> string binary, But how do I convert back? Below is a example. The output is : 'f' to binary: 01100110 294984

I read somewhere that I could use the Integer.parseInt but clearly that is not the case :( Or am I doing something wrong?

Thanks, :)

public class main{
    public static void main(String[] args) {

         String s = "f";
          byte[] bytes = s.getBytes();
          StringBuilder binary = new StringBuilder();
          for (byte b : bytes)
          {
             int val = b;
             for (int i = 0; i < 8; i++)
             {
                binary.append((val & 128) == 0 ? 0 : 1);
                val <<= 1;
             }
             binary.append(' ');
          }
          System.out.println("'" + s + "' to binary: " + binary);

        System.out.println(Integer.parseInt("01100110", 2));
    }
}

You can use Byte.parseByte() with a radix of 2:

byte b = Byte.parseByte(str, 2);

Using your example:

System.out.println(Byte.parseByte("01100110", 2));

102

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