問題描述

如果你有二進制數 10110，我怎樣才能讓它返回 5?例如一個數字，它告訴我們使用了多少位?下面列出了一些類似的例子:

If you have the binary number 10110 how can I get it to return 5? e.g a number that tells how many bits are used? There are some likewise examples listed below:

• 101 應該返回 3
• 000000011 應該返回 2
• 11100 應該返回 5
• 101010101 應該返回 9

如何在 Java 中以最簡單的方式獲得它?我想出了以下方法，但我可以做得更快嗎:

How can this be obtained the easiest way in Java? I have come up with the following method but can i be done faster:

public static int getBitLength(int value)
{
    if (value == 0)
    {
        return 0;
    }
    int l = 1;
    if (value >>> 16 > 0) { value >>= 16; l += 16; }
    if (value >>> 8 > 0) { value >>= 8; l += 8; }
    if (value >>> 4 > 0) { value >>= 4; l += 4; }
    if (value >>> 2 > 0) { value >>= 2; l += 2; }
    if (value >>> 1 > 0) { value >>= 1; l += 1; }
    return l;
}

推薦答案

最簡單?

32 - Integer.numberOfLeadingZeros(value)

如果您正在尋找算法，Java API 的實現者同意您的分而治之的位移方法:

If you are looking for algorithms, the implementors of the Java API agree with your divide-and-conquer bitshifting approach:

public static int numberOfLeadingZeros(int i) {
    if (i == 0)
        return 32;
    int n = 1;
    if (i >>> 16 == 0) { n += 16; i <<= 16; }
    if (i >>> 24 == 0) { n +=  8; i <<=  8; }
    if (i >>> 28 == 0) { n +=  4; i <<=  4; }
    if (i >>> 30 == 0) { n +=  2; i <<=  2; }
    n -= i >>> 31;
    return n;
}

編輯:提醒那些相信浮點計算準確性的人，運行以下測試工具:

Edit: As a reminder to those who trust in the accuracy of floating point calculations, run the following test harness:

public static void main(String[] args) {
    for (int i = 0; i < 64; i++) {
        long x = 1L << i;
        check(x);
        check(x-1);
    }
}

static void check(long x) {
    int correct = 64 - Long.numberOfLeadingZeros(x);
    int floated = (int) (1 + Math.floor(Math.log(x) / Math.log(2)));
    if (floated != correct) {
        System.out.println(Long.toString(x, 16) + " " + correct + " " + floated);
    }
}

第一個檢測到的偏差是:

The first detected deviation is:

ffffffffffff 48 49

這篇關于計數 int 中使用的位的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！