問題描述

我想知道在 Java 中修復精度錯誤的最佳方法是什么.正如您在以下示例中看到的那樣，存在精度錯誤:

I'm wondering what the best way to fix precision errors is in Java. As you can see in the following example, there are precision errors:

class FloatTest
{
  public static void main(String[] args)
  {
    Float number1 = 1.89f;
    
    for(int i = 11; i < 800; i*=2)
    {
      System.out.println("loop value: " + i);
      System.out.println(i*number1);
      System.out.println("");
    }
  }
}

顯示的結果是:

循環值:11

20.789999

循環值:22

41.579998

循環值:44

83.159996

循環值:88

166.31999

循環值:176

332.63998

循環值:352

665.27997

循環值:704

1330.5599

另外，如果有人能解釋為什么它只從 11 開始，并且每次都將價值翻倍.我認為所有其他值(或至少其中許多值)都顯示了正確的結果.

Also, if someone can explain why it only does it starting at 11 and doubling the value every time. I think all other values (or many of them at least) displayed the correct result.

這樣的問題過去讓我很頭疼，我通常使用數字格式化程序或將它們放入字符串中.

Problems like this have caused me headache in the past and I usually use number formatters or put them into a String.

正如人們所提到的，我可以使用雙精度，但在嘗試之后，似乎 1.89 作為雙倍乘以 792 仍然會輸出錯誤(輸出為 1496.8799999999999).

As people have mentioned, I could use a double, but after trying it, it seems that 1.89 as a double times 792 still outputs an error (the output is 1496.8799999999999).

我想我會嘗試其他解決方案，例如 BigDecimal

I guess I'll try the other solutions such as BigDecimal

推薦答案

如果你真的很在意精度，你應該使用 BigDecimal

If you really care about precision, you should use BigDecimal

https://docs.oracle.com/javase/8/docs/api/java/math/BigDecimal.html

https://docs.oracle.com/en/java/javase/11/docs/api/java.base/java/math/BigDecimal.html

這篇關于Java中浮點數的精度錯誤的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！