問題描述
我正在制作一個讀取 XML Internet 的 Android 應用程序.此應用程序使用 SAX 來解析 XML.這是我的解析部分代碼:
I'm making an Android application that reads an XML Internet. This application uses SAX to parse XML. This is my code for the part of parsing:
public LectorSAX(String url){
try{
SAXParserFactory spf=SAXParserFactory.newInstance();
SAXParser sp = spf.newSAXParser();
DefaultHandler lxmlr=new LibraryXMLReader() ;
sp.parse(url, lxmlr);
nodo=((LibraryXMLReader)lxmlr).getNodoActual();
}catch(ParserConfigurationException e){
System.err.println("Error de parseo en LectorSAX.java: "+e);
}catch(SAXException e){
System.err.println("Error de sax LectorSAX.java: " + e);
} catch (IOException e){
System.err.println("Error de io LectorSAX.java: " + e);
}
}
問題是發生了 SAXException.異常信息如下:
The problem is that SAXException occurs. The exception message is as follows:
org.apache.harmony.xml.ExpatParser$ParseException:在第 4 行,第 4 列42:格式不正確(無效令牌)
org.apache.harmony.xml.ExpatParser$ParseException: At line 4, column 42: not well-formed (invalid token)
但是,如果我將相同的代碼放入普通的 Java SE 應用程序中,則不會發生此異常并且一切正常.
However, if I put the same code in a normal Java SE application, this exception does not occur and everything works fine.
為什么相同的代碼在 Java SE 應用程序中運行良好,而不是在 Android 中運行?另一方面,如何解決這個問題?
Why the same code works fine in a Java SE application, not an Android?. On the other hand, How to solve the problem?.
感謝您的幫助.
您好.
推薦答案
這可能是字符編碼問題.
如您所見,無效令牌錯誤指向第 4 行.
在這一行中,您可以找到一個銳號 (Meteorología) 和一個波浪號 (Espa?a).XML 標頭顯示 ISO-8859-15 編碼值.由于它不如 UTF 或 ISO-8859-1 編碼常見,因此當 SAXParser 連接并嘗試使用系統默認字符集將字節內容轉換為字符時,這可能會導致錯誤.
This could be a character encoding problem.
As you can see, the invalid token error points to the line #4.
In this line, you can find an acute (Meteorología) and a tilde (Espa?a).
The XML header shows a ISO-8859-15 encoding value. As it's less common than UTFs or ISO-8859-1 encodings, this could result in a error when the SAXParser connects and try to convert the byte content into chars using your system default charset.
然后,您需要告訴 SAXParser 使用哪個字符集.一種方法是傳遞 InputSource,而不是 URL,到 parse 方法.舉個例子:
Then, you'll need to tell the SAXParser which charset to use. A way to do so, is to pass an InputSource, instead of the URL, to the parse method. As an example:
SAXParserFactory factory = SAXParserFactory.newInstance();
SAXParser parser = factory.newSAXParser();
InputSource is = new InputSource(url);
is.setEncoding("ISO-8859-15");
DefaultHandler lxmlr=new LibraryXMLReader() ;
sp.parse(is, lxmlr);
Android VM 似乎不支持這種編碼,拋出 org.apache.harmony.xml.ExpatParser$ParseException: At line 1, column 0: unknown encoding
異常.
作為 ISO-8859-15,它主要與 ISO-8859-1 兼容,除了一些特定字符(如您所見 here),解決方法是在 setEncoding 方法中將 ISO-8859-15
值更改為 ISO-8859-1
,強制解析器使用不同但兼容的字符集編碼:
It seems that Android VM does not support this encoding, throwing a org.apache.harmony.xml.ExpatParser$ParseException: At line 1, column 0: unknown encoding
exception.
As ISO-8859-15 it's mainly compatible with ISO-8859-1, except some specific characters (as you can see here), a workaround is changing the ISO-8859-15
value to ISO-8859-1
at the setEncoding method, forcing the parser to use a different but compatible charset encoding:
is.setEncoding("ISO-8859-1");
看起來,由于 Android 不支持聲明的字符集,它使用其默認 (UTF-8),因此解析器無法使用 XML 聲明來選擇適當的編碼.
As it seems, as Android doesn't support the declared charset, it uses its default (UTF-8) and hence the parser can't use the XML declaration to choose the apropiate encoding.
這篇關于Sax - ExpatParser$ParseException的文章就介紹到這了,希望我們推薦的答案對大家有所幫助,也希望大家多多支持html5模板網!