本文介紹了5秒后Android關閉對話框?的處理方法,對大家解決問題具有一定的參考價值,需要的朋友們下面隨著小編來一起學習吧!
問題描述
我正在開發一個無障礙應用.當用戶想離開應用程序時,我會顯示一個對話框,他必須在其中確認他想離開,如果他在 5 秒后未確認,則對話框應自動關閉(因為用戶可能不小心打開了它).這類似于您更改屏幕分辨率時在 Windows 上發生的情況(出現警告,如果您不確認,它會恢復到以前的配置).
I'm working on an accesibility app. When the user wants to leave the app I show a dialog where he has to confirm he wants to leave, if he doesn't confirm after 5 seconds the dialog should close automatically (since the user probably opened it accidentally). This is similar to what happens on Windows when you change the screen resolution (an alert appears and if you don't confirm it, it reverts to the previous configuration).
這就是我顯示對話框的方式:
This is how I show the dialog:
AlertDialog.Builder dialog = new AlertDialog.Builder(this).setTitle("Leaving launcher").setMessage("Are you sure you want to leave the launcher?");
dialog.setPositiveButton("Confirm", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int whichButton) {
exitLauncher();
}
});
dialog.create().show();
如何在顯示 5 秒后關閉對話框?
How can I close the dialog 5 seconds after showing it?
推薦答案
final AlertDialog.Builder dialog = new AlertDialog.Builder(this).setTitle("Leaving launcher").setMessage("Are you sure you want to leave the launcher?");
dialog.setPositiveButton("Confirm", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int whichButton) {
exitLauncher();
}
});
final AlertDialog alert = dialog.create();
alert.show();
// Hide after some seconds
final Handler handler = new Handler();
final Runnable runnable = new Runnable() {
@Override
public void run() {
if (alert.isShowing()) {
alert.dismiss();
}
}
};
alert.setOnDismissListener(new DialogInterface.OnDismissListener() {
@Override
public void onDismiss(DialogInterface dialog) {
handler.removeCallbacks(runnable);
}
});
handler.postDelayed(runnable, 10000);
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