問題描述
基本上，我使用以下代碼將字符串解析為 LocalDateTime，這在大多數(shù)情況下都可以正常工作.
DateTimeFormatter dtformatter = DateTimeFormatter.ofPattern("yyyyMMddHHmmssSSS");但是，我遇到秒和毫秒為 00000 的情況，這是解析器失敗并打印 LocalDateTime 2018-03-01T09:16 而不是 2018-03-01T09:16:00.000.
System.out.println(LocalDateTime.parse("20180301091600000",dtformatter));(請注意，在我的代碼中，我必須將字符串解析為 LocalDateTime，進行一些比較，然后最后將 LocalDateTime 打印到 csv)
如何修復它以使其打印 2018-03-01T09:16:00.000 而不是 2018-03-01T09:16 ?
僅供參考，我正在使用 jdk10.
我不知道為什么它不起作用，它似乎是一個 bug 因為當我使用:
20180301091600001 結果是 2018-03-01T09:16:00.001----------------^ -----------------^^^^^^還有另一個測試:
2018030100000000 結果是 2018-03-01T00:00--------^^^------------------^^^^^^^^^^^解析器好像忽略了秒和毫秒為零的時候，為什么?
為什么?的完整解釋在 Basil Bourque 的回答中.p>
解決方案
這是一個快速修復，您可以使用其他格式化程序，如下所示:
var 結果 = LocalDateTime.parse("20180301091600000", dtformatter).format(DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss:SSS"));輸出
2018-03-01T09:16:00:000Basically, I am using the following code to parse string as LocalDateTime, which works fine most of the time.
DateTimeFormatter dtformatter = DateTimeFormatter.ofPattern("yyyyMMddHHmmssSSS");
However, I encounter cases where the seconds and millseconds are 00000 and this is when the parser fails and print a LocalDateTime 2018-03-01T09:16 instead of 2018-03-01T09:16:00.000.
System.out.println(LocalDateTime.parse("20180301091600000",dtformatter));
(Note that in my code, I have to parse string as LocalDateTime, do some comparison and then at the end, print LocalDateTime to csv)
How can I fix it to make it print 2018-03-01T09:16:00.000 instead of 2018-03-01T09:16 ?
FYI, I am using jdk10.
I'm not sure why it's not work, it seems it is a bug because when I use :
20180301091600001 result is 2018-03-01T09:16:00.001
----------------^ -----------------^^^^^^
Also another test :
2018030100000000 result is 2018-03-01T00:00
--------^^^----- -----------^^^^^^^^^^^
It seems that the parser ignore the seconds and millisecond when it is zero, why?
The full explanation why?, is in the answer of Basil Bourque.
Solution
Here is a quick fix where you can use another formatter like this :
var result = LocalDateTime.parse("20180301091600000", dtformatter)
.format(DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss:SSS"));
Output
2018-03-01T09:16:00:000
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