本文介紹了必須使用活動訪問令牌來查詢有關當前用戶的信息的處理方法,對大家解決問題具有一定的參考價值,需要的朋友們下面隨著小編來一起學習吧!
問題描述
我在使用簡單代碼時不斷收到標題中的錯誤:
I keep getting the error in the title, while using a simple code:
require_once('sdk/src/facebook.php');
require_once("AppInfo.php");
function idx(array $array, $key, $default = null) {
return array_key_exists($key, $array) ? $array[$key] : $default;
}
function he($str) {
return htmlentities($str, ENT_QUOTES, "UTF-8");
}
$facebook = new Facebook(array(
'appId' => AppInfo::appID(),
'secret' => AppInfo::appSecret(),
'sharedSession' => true,
'trustForwarded' => true,
));
$arrayForJSON=array();
$user = $facebook->getUser();
$friends = idx($facebook->api('/me/friends'), 'data', array());
if ($friends) {
$arrayForJSON['friends']=$friends;
}
print_r($friends);
我真的不知道如何解決它,我一直在stackoverflow上搜索并嘗試了很多答案
I really don't know how to solve it, I've been searching and trying many answers on stackoverflow
推薦答案
如果沒有重定向用戶到登錄鏈接,則需要檢查是否已經登錄
you need to check if already login if not redirect the user to login link
require '../src/facebook.php';
// Create our Application instance (replace this with your appId and secret).
$facebook = new Facebook(array(
'appId' => '191149314281714',
'secret' => '73b67bf1c825fa47efae70a46c18906b',
));
// Get User ID
$user = $facebook->getUser();
// We may or may not have this data based on whether the user is logged in.
//
// If we have a $user id here, it means we know the user is logged into
// Facebook, but we don't know if the access token is valid. An access
// token is invalid if the user logged out of Facebook.
if ($user) {
try {
// Proceed knowing you have a logged in user who's authenticated.
// $user_profile = $facebook->api('/me');
$friends = idx($facebook->api('/me/friends'), 'data', array());
} catch (FacebookApiException $e) {
error_log($e);
$user = null;
}
}
// Login or logout url will be needed depending on current user state.
if ($user) {
$logoutUrl = $facebook->getLogoutUrl();
} else {
$loginUrl = $facebook->getLoginUrl(array('scope'=>'offline_access'));
}
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