問題描述
只是好奇
$files = glob(cacheme_directory()."*");
foreach($files as $file)
{
$filemtime=filemtime ($file);
if (time()-$filemtime>= 172800)
{
unlink($file);
}
}
我只想確定代碼是否正確.謝謝.
I just want to make sure if the code is correct or not. Thanks.
推薦答案
你應(yīng)該添加一個(gè) is_file() 檢查，因?yàn)?PHP 通常會(huì)列出 .和 ..，以及可能駐留在您正在檢查的目錄中的子目錄.
You should add an is_file() check, because PHP normally lists . and .., as well as sub-directories that could reside in the the directory you're checking.
此外，正如此答案所建議的，您應(yīng)該用更具表現(xiàn)力的符號(hào)替換預(yù)先計(jì)算的秒數(shù).>
Also, as this answer suggests, you should replace the pre-calculated seconds with a more expressive notation.
<?php
$files = glob(cacheme_directory()."*");
$now = time();
foreach ($files as $file) {
if (is_file($file)) {
if ($now - filemtime($file) >= 60 * 60 * 24 * 2) { // 2 days
unlink($file);
}
}
}
?>
或者，您也可以使用 DirectoryIterator、如本答案所示.在這種簡單的情況下，它并沒有真正提供任何優(yōu)勢，但它會(huì)是 OOP 方式.
Alternatively you could also use the DirectoryIterator, as shown in this answer. In this simple case it doesn't really offer any advantages, but it would be OOP way.
這篇關(guān)于在PHP中刪除所有超過2天的文件的正確方法的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網(wǎng)！