問題描述

我有一個名為 Accounts 的控制器，帶有登錄和注銷視圖.

I have a controller called Accounts, with the views signin and signout.

對應的函數如下:

function signin()
{
    if (!empty($this->data)) 
    {
        //handle login
        ...
        //save login to session
        $this->Session->write('Account',  $data["Account"]);
        //redirect to previous page
        ???
    }
}

function signout()
{
    //delete login
    $this->Session->delete('Account');
    //redirect to previous page
    ??? 
}

如果用戶轉到 accounts/signin 它首先檢查表單是否被提交 if(!empty($this->data)) 如果是，它會登錄它們，如果不是，它會呈現登錄表單.如果他們成功登錄，我想將他們重定向到他們在登錄頁面之前所在的頁面.

If the user goes to accounts/signin it first checks to see if the form is submited if(!empty($this->data)) if yes, it logs them in, if not it renders the signin form. If they do succesfully log in, I want to redirect them to the page they were at before the signin page.

最好的方法是什么?

我不認為我可以使用常規的 http 引薦來源網址，因為從技術上講，引薦來源網址將始終是登錄頁面，因為他們轉到 /signin，然后提交登錄表單.因此，在提交表單時，引用者始終是 /signin.我想重定向到他們之前所在的位置.有意義嗎?

I do not think I can user a regular http referrer because technically the referrer will always be the signin in page because they go to /signin, then submit the sign in form. So at the point where the form is submited the referrer is always /signin. I want to redirect to where they were before that. Does that make sense?

推薦答案

http://book.cakephp.org/view/430/referer

使用隱藏的 字段，該字段保存初始引用者并與登錄數據一起提交.

Use a hidden <input> field that holds the initial referrer and gets submitted with the login data.

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