問題描述

我有一個類似這個問題的問題

i have a problem similar to this question

如何在 CakePHP 中識別活動菜單鏈接

我的 default.ctp 文件中有一個頁面，我想在其中添加活動"類的鏈接.我如何識別頁面的當前 url，然后在鏈接上應用該類.. 我也在那里遵循了

i have a page in my default.ctp file in which i want to add 'active' class on links. how can i identify the current url of the page and then apply the class on link.. i have followed the answer also there which is

      $url = $this->Html->url('INPUT_THE_URL') ;
     $active = $this->request->here == $url? true: false;

我不知道如何在我的代碼中做到這一點..很抱歉我是cakephp的新手..這是我的代碼

i dont know how can i do this in my code .. sorry for asking as i am newbie in cakephp .. here is my code

 **default.ctp file** 

 <li>
      <?php echo $this->Html->link('Dashboard', array('controller'=>'users','action' => 'controlpanel'), array('title' => 'Dashboard','class' => 'shortcut-dashboard'));?></li>



  <li> <?php echo $this->Html->link('Contacts', array('controller'=>'contacts','action' => 'index'), array('title' => 'Contacts','class' => 'shortcut-contacts'));?></li>

我想像這樣添加一個帶有 li 的類

i want to add a class with li like this

   <li class = 'active''>

推薦答案

這是一個簡單的邏輯如下

This is a simple logic as follows

<li class="<?php echo (!empty($this->params['action']) && ($this->params['action']=='controlpanel') )?'active' :'inactive' ?>">
  <?php echo $this->Html->link('Dashboard', array('controller'=>'users','action' => 'controlpanel'), array('title' => 'Dashboard','class' => 'shortcut-dashboard'));?>
</li>

<li class="<?php echo (!empty($this->params['action']) && ($this->params['action']=='index') )?'active' :'inactive' ?>">
  <?php echo $this->Html->link('Contacts', array('controller'=>'contacts','action' => 'index'), array('title' => 'Contacts','class' => 'shortcut-contacts'));?></li>

這篇關于如何在 CakePhp 的當前頁面中添加活動類的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！