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if(!isset($_POST['tos']))$this->errors[] = '請接受我們的服務(wù)條款.';

<標(biāo)簽><input type="checkbox" name="tos" value="0">我同意<a href="#">服務(wù)條款</a>和<a href="#">隱私政策</a>

 <form role="form" method="POST" action="<?php echo $_SERVER['PHP_SELF'];?>"><div class="form-group"><div class="row"><div class="col-sm-6"><label for="firstname">Firstname</label><input type="text" class="form-control" id="firstname" name="firstname" placeholder="Firstname">

<div class="col-sm-6"><label for="password2">重復(fù)密碼</label><input type="password" class="form-control" id="rpass2" name="rpass2" placeholder="密碼">

<div class="checkbox"><標(biāo)簽><input type="checkbox" name="tos" value="0">我同意<a href="#">服務(wù)條款</a>和<a href="#">隱私政策</a>

<input type="hidden" name="secur" value="<?php echo $ip;?>"/><input type="hidden" name="token" value="<?php echo $token;?"/><button type="submit" name="register" class="btn btn-block btn-color btn-xxl">創(chuàng)建賬戶</button></表單>

這段代碼有什么問題?任何幫助將不勝感激.

if(!isset($_POST['tos']))$this->errors[] = '請接受我們的服務(wù)條款.';`

這是說如果 $_POST 中沒有tos"，則拋出錯(cuò)誤.

你真的應(yīng)該用javascript檢查這個(gè)客戶端，在表單被發(fā)送到服務(wù)器之前.

你也可以...

和 PHP:

if(isset($_POST['tos']) && $_POST['tos']==='accepted') echo 'All good';else array_push($errors,'此處的錯(cuò)誤代碼');//添加到$error數(shù)組

更新

我不確定您是否在使用 jQuery，但只是為了更用戶友好的方法:

var tos = $('#tos');var notice = $('.notice');tos.on('點(diǎn)擊',function(){if(tos.is(':checked')){notice.text('謝謝你.');}別的{notice.text('請接受我們的 ToS 以繼續(xù).');}})

在此處查看工作示例. 如果未選中，您甚至可以一起暫停表單.順便說一句，如果我沒記錯(cuò)的話 checkbox 輸入只發(fā)送 POST 數(shù)據(jù) if 選中.

I am trying to check if a checkbox have been checked in PHP in order to register. But it's not working right now. This is the code I am using so far, to check if it have been checked.

if(!isset($_POST['tos']))
  $this->errors[] = 'Please accept our Terms of Service.';

And this is the HTML code.

<div class="checkbox">
<label>
<input type="checkbox" name="tos" value="0"> I agree to the <a href="#">Terms of Service</a> and <a href="#">Privacy Policy</a>
</label>
</div>

Full form code:

        <form role="form" method="POST" action="<?php echo $_SERVER['PHP_SELF'];?>">
              <div class="form-group">

              <div class="row">
                  <div class="col-sm-6">
                  <label for="firstname">Firstname</label>
                  <input type="text" class="form-control" id="firstname" name="firstname" placeholder="Firstname">
                  </div>
                  <div class="col-sm-6">
                  <label for="surname">Surname</label>
                  <input type="text" class="form-control" id="surname" name="surname" placeholder="Surname">
                  </div>
              </div>
              </div>
              <div class="form-group">
                <label for="username">Username</label>
                <input type="text" class="form-control" id="ruser" name="ruser" placeholder="Username">
              </div>
              <div class="form-group">
                <label for="email2">Email address</label>
                <input type="email" class="form-control" id="remail" name="remail" placeholder="Enter email">
              </div>
              <div class="form-group">
                <div class="row">
                  <div class="col-sm-6">
                  <label for="password2">Password</label>
                  <input type="password" class="form-control" id="rpass" name="rpass" placeholder="Password">
                  </div>
                  <div class="col-sm-6">
                  <label for="password2">Repeat password</label>
                  <input type="password" class="form-control" id="rpass2" name="rpass2" placeholder="Password">
                  </div>
                </div>
              </div>
              <div class="checkbox">
                <label>
                  <input type="checkbox" name="tos" value="0"> I agree to the <a href="#">Terms of Service</a> and <a href="#">Privacy Policy</a>
                </label>
              </div>
               <input type="hidden" name="secur" value="<?php echo $ip;?>"/>
               <input type="hidden" name="token" value="<?php echo $token;?>"/>
              <button type="submit" name="register" class="btn btn-block btn-color btn-xxl">Create an account</button>
            </form>

What's wrong with this code? Any help would be appreciated.

if(!isset($_POST['tos']))
  $this->errors[] = 'Please accept our Terms of Service.';`

What this is doing is saying if there is no 'tos' in $_POST, throw an error.

Really you should probably check this client side with javascript, before the form is sent to the server.

You could also...

<input type="checkbox" name="tos" value="accepted" checked>

And PHP:

if(isset($_POST['tos']) && $_POST['tos']==='accepted') echo 'All good'; 
else array_push($errors,'err code here'); //to add to $error array

Update

I'm not sure if you're using jQuery or not, but just for a more user friendly approach:

var tos = $('#tos');
var notice = $('.notice');
tos.on('click',function(){
  if(tos.is(':checked')){
    notice.text('Thank you.');
  }
  else{
   notice.text('Please accept our ToS to continue.');
  }
})

See a working example here. You could even halt the form all together if it's unchecked. BTW, if I remember correctly checkbox inputs only send POST data if checked.

這篇關(guān)于如何檢查復(fù)選框是否在 PHP 中被選中?的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網(wǎng)！

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