本文介紹了如何使用數(shù)據(jù)庫(kù)中的值填充 HTML 下拉列表的處理方法,對(duì)大家解決問(wèn)題具有一定的參考價(jià)值,需要的朋友們下面隨著小編來(lái)一起學(xué)習(xí)吧!
問(wèn)題描述
作為我正在創(chuàng)建的 HTML 表單的一部分,我想要一個(gè)下拉列表,該列表將列出我數(shù)據(jù)庫(kù)中的所有用戶名.
as part of a HTML form I am creating I would like to have a dropdown list which will list all the usernames in my database.
我認(rèn)為以下代碼可以解決問(wèn)題,但下拉列表是空的 - 有人可以幫助我解決我做錯(cuò)了什么嗎?謝謝.
I thought the following code would do the trick but the dropdown list is empty - could someone assist me in what i'm doing wrong? Thanks.
<tr>
<td>Owner</td>
<td>
<select name="owner">
<?php
$sql = mysqli_query($connection, "SELECT username FROM users");
while ($row = $sql->fetch_assoc()){
?>
<option value="owner1"><?php echo $row['username']; ?></option>
<?php
// close while loop
}
?>
</td>
</tr>
推薦答案
我猜你有問(wèn)題,因?yàn)槟銢](méi)有在循環(huán)后關(guān)閉你的選擇標(biāo)簽.這能解決問(wèn)題嗎?
My guess is that you have a problem since you don't close your select-tag after the loop. Could that do the trick?
<select name="owner">
<?php
$sql = mysqli_query($connection, "SELECT username FROM users");
while ($row = $sql->fetch_assoc()){
echo "<option value="owner1">" . $row['username'] . "</option>";
}
?>
</select>
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