問題描述

我有這樣的數(shù)據(jù)庫表:

shoot: id, name, programme
programme: id, name

拍攝中的雄辯關(guān)系是這樣定義的:

The eloquent relationship in the shoot is defined like this:

public function programme() {
    return $this->belongsTo('AppProgramme', 'programme', 'id');
}

使用 dd() 時，我可以看到這是正常工作的:

When using dd(), I can see this is working correctly:

dd(Shoot:where('id','=',1)->with('programme')->first());
// prints the object with programme listed under the relationship

但是，當(dāng)我急切加載拍攝并嘗試獲取程序?qū)ο髸r，我反而檢索了拍攝屬性程序".例如:

However when I eager-load the shoot and attempt to get the programme object, I retrieve the shoot attribute "programme" instead. E.g.:

$shoot = Shoot:where('id','=',1)->with('programme')->first();
echo $shoot->programme; // returns 1, not AppProgramme object.

有沒有無需重寫大量代碼庫的解決方案?

Is there a solution to this without having to rewrite masses of the codebase?

推薦答案

relationship 和 column 名稱不應(yīng)使用相同的名稱，否則您將將始終收到 column 名稱，因此嘗試編輯其中之一，我認(rèn)為這里最簡單的是 relationship 名稱:

You shouldn't use the same name for the both relationship and column name, else you'll receive always the column name so try to edit one of them, I think the easiest one here is the relationship name :

public function programmeObj() {
    return $this->belongsTo('AppProgramme', 'programme', 'id');
}

然后將其稱為:

echo $shoot->programmeObj;

注意:但如果你想遵循約定，你應(yīng)該用 programme_id 替換 name 屬性，所以:

NOTE : But if you want to follow conventions you should replace the name attribute by programme_id so :

public function programme() {
    return $this->belongsTo('AppProgramme', 'programme_id', 'id');
}

希望這會有所幫助.

這篇關(guān)于Laravel 獲取與其屬性同名的 Eloquent 關(guān)系的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網(wǎng)！