問(wèn)題描述

我正在嘗試為這樣的 Eloquent 關(guān)系分頁(yè):

I am trying to paginate a Eloquent relationship like this:

 $query = Product::find(1)->options()->paginate();

但我收到以下錯(cuò)誤:

Fatal error: Call to a member function getCurrentPage() on a non-object

我已經(jīng)確認(rèn)代碼 $query = Product::find(1)->options() 返回一個(gè)選項(xiàng)集合.$query 對(duì)象似乎是 hasMany 類(lèi)型.以下是我正在使用的模型類(lèi).

I have confirmed that the code $query = Product::find(1)->options() returns a collection of options. The $query object seems to be of type hasMany. Below are the model classes I am using.

class Product extends Eloquent
{

    protected $table = 'products';

    public function options ()
    {
        return $this->hasMany('ProductOption', 'product_id');
    }
}

class ProductOption extends Eloquent
{
    protected $table = 'product_options';

    public function product()
    {
        return $this->belongsTo('Product', 'product_id');
    }
}

eloquent 不返回關(guān)系的分頁(yè)結(jié)果嗎?

Does eloquent not return paginated results for relationships?

推薦答案

你不能像這樣延遲加載關(guān)系分頁(yè)，而是在你的產(chǎn)品模型中把以下函數(shù)放在你的選項(xiàng)下面有很多關(guān)系

You can not lazy load relational pagination like that, instead in your Product Model put the following function below your options has many relationship

public function getOptionsPaginatedAttribute()
{
    return $this->options()->paginate(10);
}

這將允許您通過(guò)

$product->options_paginated

這篇關(guān)于Laravel Eloquent 關(guān)于關(guān)系的分頁(yè)的文章就介紹到這了，希望我們推薦的答案對(duì)大家有所幫助，也希望大家多多支持html5模板網(wǎng)！