問題描述
有沒有一種簡單的方法來計算 Python 中 N 個列表的元素總和?我知道如果我們有n個列表定義(調(diào)用第i個列表c_i)，我們可以這樣做:
Is there an easy way to compute the element-wise sum of N lists in python? I know if we have n lists defined (call the ith list c_i), we can do:
z = [sum(x) for x in zip(c_1, c_2, ...)]
例如:
c1 = [1,2]
c2 = [3,4]
c3 = [5,6]
z = [sum(x) for x in zip(c1,c2,c3)]
這里z = [9, 12]
但是如果我們沒有定義 c_i 而是在列表 C 中有 c_1...c_n 怎么辦?
But what if we don't have c_i defined and instead have c_1...c_n in a list C?
如果我們只有 C，有沒有類似的方法可以找到 z?
Is there a similar way to find z if we just have C?
我希望這很清楚.
已解決:我想知道 * 運算符是什么意思...謝謝！
resolved: I was wondering what the * operator was all about...thanks!
推薦答案
這樣做:
[sum(x) for x in zip(*C)]
在上面，C是c_1...c_n的列表.正如評論中的 鏈接 中所述(感謝@kevinsa5！):
In the above, C is the list of c_1...c_n. As explained in the link in the comments (thanks, @kevinsa5!):
* 是splat"運算符:它將一個列表作為輸入，并將其擴(kuò)展為函數(shù)調(diào)用中的實際位置參數(shù).
*is the "splat" operator: It takes a list as input, and expands it into actual positional arguments in the function call.
有關(guān)更多詳細(xì)信息，請查看 文檔，在解包參數(shù)列表"下，還閱讀了有關(guān) 調(diào)用 (謝謝@abarnert！)
For additional details, take a look at the documentation, under "unpacking argument lists" and also read about calls (thanks, @abarnert!)
這篇關(guān)于N個列表元素的總和python的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網(wǎng)！