問題描述

我正在嘗試找出一種方法，通過 fetchMesasges() 和 before 使用循環(huán)來獲取不和諧的舊消息.我想使用循環(huán)獲得超過 100 的限制，但我無法弄清楚，我能找到的每篇文章都只討論如何使用循環(huán)刪除超過 100 的限制，我只需要檢索它們.

I'm trying to figure out a way to use loops to get old messages on discord using fetchMesasges() and before. I'd like to get more than the 100 limit using a loop but I cannot figure it out, and every post I can find only discuss how to use loops to DELETE more than the 100 limit, I just need to retrieve them.

我是編碼新手，尤其是 javascript，所以我希望有人可以幫助我朝著正確的方向前進(jìn).

I'm new to coding and javascript in particular so I'm hoping someone can give me a nudge in the right direction.

這是我能夠設(shè)法檢索超過 100 條消息的唯一方法(在多次嘗試使用循環(huán)失敗之后):

Here is the only way I could manage to retrieve messages that are farther than 100 back(after many failed attempts at using loops):

channel.fetchMessages({ limit: 100 })
    .then(msg => {
        let toBeArray = msg;
        let firstLastPost = toBeArray.last().id;

        receivedMessage.channel
            .fetchMessages({ limit: 100, before: firstLastPost })
            .then(msg => {
                let secondToBeArray = msg;
                let secondLastPost = secondToBeArray.last().id;

                receivedMessage.channel
                    .fetchMessages({ limit: 100, before: secondLastPost })
                    .then(msg => {
                        let thirdArray = msg;
                        let thirdLastPost = thirdArray.last().id;

                        receivedMessage.channel
                            .fetchMessages({ limit: 100, before: thirdLastPost })
                            .then(msg => {
                                let fourthArray = msg;
                            });
                    });
            });
    });

推薦答案

你可以做的是使用 async/await 函數(shù)和一個循環(huán)來發(fā)出順序請求

What you can do is use an async/await function and a loop to make sequntial requests

async function lots_of_messages_getter(channel, limit = 500) {
    const sum_messages = [];
    let last_id;

    while (true) {
        const options = { limit: 100 };
        if (last_id) {
            options.before = last_id;
        }

        const messages = await channel.fetchMessages(options);
        sum_messages.push(...messages.array());
        last_id = messages.last().id;

        if (messages.size != 100 || sum_messages >= limit) {
            break;
        }
    }

    return sum_messages;
}

這篇關(guān)于獲取超過 100 條消息的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網(wǎng)！