問題描述

所以我有一個(gè)對象數(shù)組如下:

So I have an object array that as follows:

var array = [
    {name:"Joe", date:'2018-07-01', amt:250 },
    {name:"Mars", date:'2018-07-01', amt:250 },
    {name:"Joe", date:'2018-07-02', amt:250 },
    {name:"Saturn", date:'2018-07-01', amt:250 },
    {name:"Joe", date:'2018-07-02', amt:250 },
    {name:"Jupiter", date:'2018-07-01', amt:250 },
]

我想根據(jù) name、amount 和 date 是否重復(fù)來過濾數(shù)據(jù).這個(gè)甚至不過濾重復(fù)的名稱.

I want to filter data depending if the name, amount and date has duplicate. This one doesn't filter even a duplicate name.

var unique = array.filter((v, i, a) =>{ return a.indexOf(v) === i});

如何根據(jù) name、amount 和 date 過濾重復(fù)項(xiàng)?

How can I filter duplicate for this one based on name, amount and date?

推薦答案

試試這個(gè)代碼，它只返回唯一的對象.

Try this code it returns unique objects only.

var data = [
{name:"Joe", date:'2018-07-01', amt:250 },
{name:"Mars", date:'2018-07-01', amt:250 },
{name:"Joe", date:'2018-07-02', amt:250 },
{name:"Saturn", date:'2018-07-01', amt:250 },
{name:"Joe", date:'2018-07-02', amt:250 },
{name:"Jupiter", date:'2018-07-01', amt:250 },
]
var resArr = [];
data.filter(function(item){
  var i = resArr.findIndex(x => (x.name == item.name && x.date == item.date && x.amt == item.amt));
  if(i <= -1){
        resArr.push(item);
  }
  return null;
});
console.log(resArr)

如果這不是你要找的，請告訴我.

Do tell me if this is not what you're looking for.

這篇關(guān)于如何從對象數(shù)組 Javascript 中獲取唯一值的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網(wǎng)！