問題描述
這是一個非常基本的問題.在電子中，如何檢查 BrowserWindow 的 url/文件名?
This is a pretty basic question. In electron, how do I check the url/filename of a BrowserWindow?
let win;
app.on('ready', () => {
win = new BrowserWindow();
win.loadFile(path.join(__dirname, 'public', 'main.html'));
win.on('closed', () => {
app.quit();
})
});
好吧，這么說，這是代碼，說在不同的(添加:插入)瀏覽器窗口中發生某個事件后，我想從主瀏覽器窗口(win)獲取 url.
Ok, so say, this is the code, say after a certain event happens in a different (add:insert) BrowserWindow, I want to get the url from the main BrowserWindow (win).
let addWin;
ipcMain.on('createAddWin', ()=>{
addWin = new BrowserWindow();
addWin.loadFile(path.join(__dirname, 'public', 'add.html'));
addWin.on('closed', () => {
addWin = null
});
ipcMain.on('add:insert', (e,insertObject) => {
//some event happens
//retrieve url from main window (win)
});
});
我該怎么做呢，我寧愿不必向 win 發送事件，然后通過 ipcRenderer 發送 url，盡管這絕對是可能的.
How do I go about this, I prefer to not have to send an event to the win to then send the url through ipcRenderer, though this is definitely possible.
推薦答案
可以使用 getURL() 窗口的 webContents 實例方法> 實例屬性:
Getting the window's URL is possible by using the getURL() instance method of the window's webContents instance property:
let currentURL = win.webContents.getURL();
這篇關于如何獲取 BrowserWindow 的 url?的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！