問題描述

gulpfile.js

gulpfile.js

gulp.task('browser-bundle', ['react'], function() {
...

});


gulp.task('react', function(){
  gulp.src(options.JSX_SOURCE)
      .pipe(react())
      .pipe(gulp.dest(options.JSX_DEST))
});

如您所見，我有瀏覽器捆綁任務(wù)，具體取決于反應(yīng)任務(wù).我相信這可以按預(yù)期工作，因?yàn)樵谳敵鲋形铱吹搅?

As you can see I have the browser-bundle task depending on the react task. I believe this works as expected because in the output I see this:

[gulp] Running 'react'...
[gulp] Finished 'react' in 3.43 ms
[gulp] Running 'browser-bundle'...

然而，雖然 react 任務(wù)已經(jīng)完成，但它應(yīng)該寫入操作系統(tǒng)的文件還沒有完全到位.我注意到，如果我在瀏覽器捆綁命令中添加了一個(gè) sleep 語句，那么它會(huì)按預(yù)期工作，但這對(duì)我來說似乎有點(diǎn) hacky.

However, although the react task is finished, the files its supposed to write to the operating system are not quite there yet. I've notice that if I put a sleep statement in the browser bundle command then it works as expected, however this seems a little hacky to me.

如果我希望在文件(來自 gulp.dest)被同步寫入磁盤之前不認(rèn)為反應(yīng)任務(wù)完成，我該怎么做?

If I want the react task to not be considered finished until the files (from gulp.dest) have been synchronously written to disk how would I do that?

推薦答案

你需要一個(gè)return語句:

You need a return statement:

gulp.task('react', function(){
    return gulp.src(options.JSX_SOURCE)
        .pipe(react())
        .pipe(gulp.dest(options.JSX_DEST))
});

這樣，我所有的寫操作都在下一個(gè)任務(wù)處理之前完成.

With this all my write operations are done before the next task processed.

這篇關(guān)于在繼續(xù)下一個(gè)任務(wù)之前使 gulp 同步寫入文件的文章就介紹到這了，希望我們推薦的答案對(duì)大家有所幫助，也希望大家多多支持html5模板網(wǎng)！