問(wèn)題描述
我需要獲取 MySQL 上幾個(gè)日期中包含的天數(shù).
I need to get the number of days contained within a couple of dates on MySQL.
例如:
- 入住日期是
12-04-2010 - 退房日期
15-04-2010
日差為 3.
推薦答案
DATEDIFF 函數(shù)?
What about the DATEDIFF function ?
引用手冊(cè)頁(yè):
DATEDIFF() 返回 expr1 – expr2表示為從一開(kāi)始的天數(shù)約會(huì)到另一個(gè).expr1 和 expr2是日期或日期和時(shí)間表達(dá)式.只有值的日期部分是用于計(jì)算
DATEDIFF() returns expr1 – expr2 expressed as a value in days from one date to the other. expr1 and expr2 are date or date-and-time expressions. Only the date parts of the values are used in the calculation
在你的情況下，你會(huì)使用:
In your case, you'd use :
mysql> select datediff('2010-04-15', '2010-04-12');
+--------------------------------------+
| datediff('2010-04-15', '2010-04-12') |
+--------------------------------------+
| 3 |
+--------------------------------------+
1 row in set (0,00 sec)
但請(qǐng)注意，日期應(yīng)寫為YYYY-MM-DD，而不是像您發(fā)布的那樣DD-MM-YYYY.
But note the dates should be written as YYYY-MM-DD, and not DD-MM-YYYY like you posted.
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