問題描述

我有一個 100 位數字，我試圖將數字的所有數字放入一個列表中，以便對它們執行操作.為此，我使用以下代碼:

I have a 100 digit number and I am trying to put all the digits of the number into a list, so that I can perform operations on them. To do this, I am using the following code:

for x in range (0, 1000):
   list[x] = number % 10
   number = number / 10

但我面臨的問題是我收到了一個溢出錯誤，比如浮點數/整數太大.我什至嘗試使用以下替代方法

But the problem I am facing is that I am getting an overflow error something like too large number float/integer. I even tried using following alternative

number = int (number / 10)

如何將這個巨大的數字除以整數類型的結果，即沒有浮點數?

How can I divide this huge number with the result back in integer type, that is no floats?

推薦答案

在 Python 3 中，number/10 將嘗試返回 float.但是，浮點值在 Python 中不能任意大，如果 number 很大，則會引發 OverflowError.

In Python 3, number / 10 will try to return a float. However, floating point values can't be of arbitrarily large size in Python and if number is large an OverflowError will be raised.

您可以使用 sys 模塊找到 Python 浮點值可以在您的系統上使用的最大值:

You can find the maximum that Python floating point values can take on your system using the sys module:

>>> import sys
>>> sys.float_info.max
1.7976931348623157e+308

要繞過此限制，請改為使用 // 從兩個整數的除法中取回一個整數:

To get around this limitation, instead use // to get an integer back from the division of the two integers:

number // 10

這將返回 number/10 的 int 底值(它不會產生浮點數).與浮點數不同，int 值可以根據您在 Python 3 中所需的大小(在內存限制內).

This will return the int floor value of number / 10 (it does not produce a float). Unlike floats, int values can be as large as you need them to be in Python 3 (within memory limits).

您現在可以劃分大數.例如，在 Python 3 中:

You can now divide the large numbers. For instance, in Python 3:

>>> 2**3000 / 10
OverflowError: integer division result too large for a float

>>> 2**3000 // 10
123023192216111717693155881327...

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